Hi all, In How to define a vector function depends on the solution? , it was suggested that one could define an Expression that depends on the solution, u, as, for example: Expression(("1/(x[0]+u0)","1/(x[1]+u1)"),u0=u.sub(0),u1=u.sub(1)) My question is, how can we do the same with an UserExpress…

How to define a UserExpression that depends on the solution?

siddhartha_harsha_om March 21, 2019, 3:28pm 6

Hi Anton,

Did you try to find a solution?
I am stuck with a similar issue (link). I have non-linear coefficients that are dependent on the trial functions as well.

may Thanks,
Sid

Non-Linear Coeffecients: dependent on trial functions;

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How to define a UserExpression that depends on the solution?

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